MCQ Practice

Consider the following implementation of the Wagner-Fischer algorithm: int get_min(int a, int b) { if(a < b) return a; return b; } int edit_distance(char *s1, char *s2) { int len1,len2,i,j,min; len1 = strlen(s1); len2 = strlen(s2); int arr[len1 + 1][len2 + 1]; for(i = 0;i <= len1; i++) arr[i][0] = i; for(i = 0; i <= len2; i++) arr[0][i] = i; for(i = 1; i <= len1; i++) { for(j = 1; j <= len2; j++) { min = get_min(arr[i-1][j],arr[i][j-1]) + 1; if(s1[i - 1] == s2[j - 1]) { if(arr[i-1][j-1] < min) ____________; } else { if(arr[i-1][j-1] + 1 < min) min = arr[i-1][j-1] + 1; } arr[i][j] = min; } } return arr[len1][len2]; } Which of the following lines should be inserted to complete the above code?

A

arr[i][j] = min

B

min = arr[i-1][j-1] - 1

C

min = arr[i-1][j-1].

D

min = arr[i-1][j-1] + 1

Correct Answer: C