If fraca^2 + b^2c^2 = fracb^2 + c^2a^2 = fracc^2 + a^2b^2 = (1)/(k), (k ne 0) th – OfficerPath

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If fraca^2 + b^2c^2 = fracb^2 + c^2a^2 = fracc^2 + a^2b^2 = (1)/(k), (k ne 0) then k =?

Subject: MathematicsTopic: Algebra

A

2

B

1

C

0

D

(1)/(2)

Correct Answer: D

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